Fotoreceptory oka Model 3D
0
Licencja bezpłatnaWszystkie rozszerzone zastosowania
Proste zwroty
Gwarancja najlepszej ceny
Działa po wyjęciu z pudełka
Specyfikacje
- Geometriapolygonal
- Wieloboki18,976,549
- Wierzchołki11,149,204
- TeksturyYes
- RiggedNo
- OżywionyNo
- Gotowy do druku 3DNo
- Game Ready (low poly)No
- Mapowanie UVYes
- Nieopakowane UVnone
Opis
The only detailed model of eye photoreceptors :). Redshift and VRay render. It consists of several types of cells:
cone cells with photoreceptor membrane discs inside
stick cells with photoreceptor membrane discs inside
amacrine cells
pigment epithelium cells
ganglionic cells
bipolar cells.
All they are connected between each to other.
It is made so that you can tile the model. I left there helpers (planes) that you could clone all the system of cells using plane dimensions.
1. VRay_Photoreceptors_Old
cone cells with photoreceptor membrane discs inside
stick cells with photoreceptor membrane discs inside
amacrine cells
pigment epithelium cells
ganglionic cells
bipolar cells.
All they are connected between each to other.
It is made so that you can tile the model. I left there helpers (planes) that you could clone all the system of cells using plane dimensions.
All models are some low with turbosmooth modifier.
There are 3 versions of the model:1. VRay_Photoreceptors_Old
3ds Max 2014 VRay 3.6 (CPU Render)
Red and Blue cells on the top.
Polys with Turbosmooth: ~19 000 000
Polys without Turbosmooth: ~10 000 000
It has Berconmap procedural texture in bump maps. But you can remove it and use some standard max.
2. VRay_Photoreceptors
3ds Max 2018 VRay 4.3 (GPU Render!)
Shades of red colors on top cells.
Polys with Turbosmooth: ~30 000 000
Polys without Turbosmooth: ~ 4 000 000
3. RedShift_Photoreceptors
3ds Max 2018 Redshift 3.2 (GPU Render)
Shades of red colors on top cells.
Polys with Turbosmooth: ~30 000 000
Polys without Turbosmooth: ~ 4 000 000
Sep 16, 2020
Data dodania
Aug 26, 2021
Ostatnia aktualizacja
Recenzje
Obecnie nie ma recenzji tego produktu.
Dlaczego nie być pierwszym, który złamie lód?

































